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Posted: Saturday, January 30, 2010 11:05:02 PM
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In soluton of sin^-1(sin5) how we can say 3pi/2<5<2pi? What is the approprite region?
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piks.satya
Posted: Sunday, February 14, 2010 11:05:38 PM
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it lies at zero deg . since sin 5= 5*2 pi = 2 pi= 0
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